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(C) When two unbiased dice are thrown,the sample space $S$ consists of $6 	imes 6 = 36$ possible outcomes:$S = \{(1,1), (1,2), (1,3), (1,4), (1,5), (

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$\frac{1}{6}$

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(C) When two unbiased dice are thrown,the sample space $S$ consists of $6 	imes 6 = 36$ possible outcomes:$S = \{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)\}$Total number of outcomes $n(S) = 36$.Let $E$ be the event that the sum of the numbers on the two dice is smaller than $5$.The possible sums smaller than $5$ are $2, 3,$ and $4$.The outcomes favourable to event $E$ are:Sum $= 2: (1,1)$Sum $= 3: (1,2), (2,1)$Sum $= 4: (1,3), (2,2), (3,1)$Thus,the number of favourable outcomes $n(E) = 1 + 2 + 3 = 6$.The probability $P(E) = \frac{n(E)}{n(S)} = \frac{6}{36} = \frac{1}{6}$.

Two unbiased dice are thrown once. Write all the possible outcomes of this experiment. What is the probability that the sum of numbers on two dice is smaller than $5$?

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